Time: 0:00
Test a custom input to verify an edge case (e.g. empty lists, negative numbers, duplicates).
This bug belongs to the logic errors pattern
The wrong operator, an inverted condition, a formula the right way round but backwards.
What went wrong: n % 2 is the remainder after dividing by 2. Even numbers give 0 and odd numbers give 1. The code checks for 1, so it finds odd numbers.
The fix: return n % 2 === 0;
Remember: test one input that should be true and one that should be false.
The pattern behind it: logic errors.
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